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Finishing touches to obtain the particular solution of a differential equation

 

I have been following the workings in my textbook on autonomous equations and could follow everything except for one step: obtaining the particular solution for y.

 

The general solution is:

de1a.png

To satisfy the initial condition  

de2a.png
de3a.png

Despite having been working on this for a good deal of time, I simply am unable to comprehend how they eventually solved for y, giving: 

de4a.png

Could you explain to me how this was arrived at?




Student X





Beginning with the general solution cited, ie

de5a.png

we proceed to invert both sides concurrently :

de6a.png

Now, making use of the substitution

de3a.png

we therefore have

de7a.png

Thereafter, this simply reduces to

de4a.png

Hope this helps. Peace.

Best Regards,

Mr Koh